D / D / 1 Example |
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6 |
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Time Period 1 (Noon
to 2 PM) |
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Qnoon = 0 |
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Q2PM = |
100 veh |
(50 veh/hr x 2 hrs.) |
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D |
Q = |
50 vph |
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Q1Avg= |
(Qnoon + Q2pm)/2 |
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Q1Avg= |
(0
+ 100)/2 = 50 |
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l = |
200 |
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m = |
150 |
vph |
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Time Period 1 (2 PM
to 8 PM) |
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Q2PM = 100 |
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Q = |
0 veh |
(25 veh/hr x X hrs.) |
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D |
Q = |
25 vph |
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l = |
125 |
vph |
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m = |
150 |
vph |
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X = |
100 veh/25 veh/hr = |
4 |
hours |
= T2 |
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Q2Avg= |
(Q2pm+Q?pm)/X |
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Q2Avg= |
(Q2pm+Q6pm)/4 |
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Q2Avg= |
(100
+ 0)/4 = 25 |
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Total Delay = D1 + D2 = Total Time in Queue = T1 * Q1avg + T2 * Q2Avg |
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where Ti = Time during period i for which a
queue exists |
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Total Delay = 2 hrs
* 50 veh + 4 hrs * 25 veh = 200
vehicle-hours |
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